I’ve come across several methods to JavaScript check if undefined:
if (window.myVariable)
if (typeof(myVariable) != "undefined")
-
if (myVariable)
— but this throws an error if the variable is undefined.
Should I use a try/catch
block for the last one, or is there a better, more reliable way to check if a variable is undefined?
Honestly, the most reliable javascript check if undefined, especially when you’re not even sure if the variable was ever declared, is using typeof
.
if (typeof myVariable !== "undefined") {
// variable exists
}
This approach won’t throw a ReferenceError
, so it’s your safest bet when you’re just trying to avoid crashing the app over a missing variable. Super handy during defensive coding or when integrating with unpredictable external scripts.
Yup, typeof
is the safest play. But if you’re already sure the variable’s declared in your scope, you can clean it up a bit. My go-to javascript check if undefined in that case:
if (myVariable === undefined) {
// yep, it's undefined
}
It’s more readable and intentional, especially when you’re debugging or writing code in a well-defined block. Just remember, it’ll break if myVariable
was never declared, so use it with scoped confidence.
Totally agree with both. I’d just add that if you’re working with deeply nested objects (think API responses), then optional chaining is a modern lifesaver for javascript check if undefined cases.
if (myObj?.someProp === undefined) {
// someProp is either missing or undefined
}
It prevents runtime errors while still giving you clarity. Especially useful when dealing with data structures that aren’t always consistent—makes your code cleaner and safer without too much overhead