How can I convert the string ‘false’ to 0 and ‘true’ to 1 in Python, where the string is of type unicode?
For example, if x == ‘true’ and type(x) == unicode, I want x to become 1.
Note: I prefer not to use if-else statements.
You know, with my experience working with Python, a straightforward approach I use to convert a ‘true’/‘false’ string to 1/0 is leveraging the int() function with a boolean expression. Like this:
x = int(x == 'true')
This way, you’re essentially comparing the string to ‘true’, and Python’s int() function will convert the boolean result into an integer—1 for ‘true’ and 0 for anything else. Simple and effective! This is a great example of using Python bool to int.
Ah, that’s a solid approach, @vindhya.rddy! If you’re looking for something a bit more flexible and clean, especially when dealing with user input, I tend to use a dictionary mapping. Here’s a snippet:
x = {'true': 1, 'false': 0}.get(x.lower(), 0)
This method takes care of any capitalization issues (with .lower()) and ensures that ‘true’ gets mapped to 1 and ‘false’ to 0. Plus, if the string isn’t exactly ‘true’ or ‘false’, it defaults to 0. It’s pretty handy, and in the context of python bool to int, it works wonderfully.
Oh, I like both those approaches! But if you’re in the mood for something a bit more functional, you could also try using the map() function with a lambda expression:
x = list(map(lambda y: 1 if y == 'true' else 0, [x]))[0]
This applies a lambda function to the string and converts it to 1 if it’s ‘true’ and 0 otherwise. It’s really neat when you’re handling lists or multiple conversions at once. So, whether you’re working with a simple comparison or need something a bit more versatile, the python bool to int conversions have a lot of options!