How can I sort an array of objects by the firstname property alphabetically using JavaScript?

General Discussions
#1

How can I sort an array of objects by the firstname property alphabetically using JavaScript?

Given the following object as part of the array:

var user = {
bio: null,
email: "user@domain.example",
firstname: "Anna",
id: 318,
lastAvatar: null,
lastMessage: null,
lastname: "Nickson",
nickname: "anny"
};

I need to know how to achieve this with sort alphabetically JavaScript.

#2

Hi,

You can use the Array.prototype.sort() method in JavaScript to sort an array of objects by the firstname property alphabetically. Here’s how to do it:

var users = [
{ firstname: "Anna", lastname: "Nickson" },
{ firstname: "John", lastname: "Doe" },
{ firstname: "Zara", lastname: "Smith" }
];
users.sort(function(a, b) {
return a.firstname.localeCompare(b.firstname); // Sorts alphabetically by firstname
});
console.log(users);

This method efficiently demonstrates how to sort alphabetically JavaScript.

#3

You can also use an arrow function for a more concise syntax when sorting the array. This will achieve the same result as the previous example:

var users = [
{ firstname: "Anna", lastname: "Nickson" },
{ firstname: "John", lastname: "Doe" },
{ firstname: "Zara", lastname: "Smith" }
];
users.sort((a, b) => a.firstname.localeCompare(b.firstname)); // Using arrow function
console.log(users);

This is another clear way to sort alphabetically JavaScript.

#4

If you need to handle case sensitivity while sorting, you can modify the comparison function to normalize the case using toLowerCase(). Here’s how you can do that:

var users = [
{ firstname: "anna", lastname: "Nickson" },
{ firstname: "John", lastname: "Doe" },
{ firstname: "zara", lastname: "Smith" }
];
users.sort((a, b) => a.firstname.toLowerCase().localeCompare(b.firstname.toLowerCase())); // Case-insensitive sort
console.log(users);

This method ensures that the sorting is not affected by case and showcases how to sort alphabetically JavaScript effectively.