How can I exit a loop in Python when a certain condition is met?

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1

How can I exit a loop in Python when a certain condition is met?

I have a loop, and I want it to stop when x + y = z. Here’s my code: from random import randint

import os

x = randint(1, 11)
y = randint(1, 11)

print("", x, "+", y, "=\n")
z = int(input("Resposta="))

if z == x + y:
    input("\n\nCorreto\nPrima enter para continuar...")

else:
    for z in range(0, 10):
        os.system('CLS')
        input("Incorreto.\n\n Tente de novo...")
        x = randint(1, 11)
        y = randint(1, 11)
        os.system('CLS')
        print("", x, "+", y, "=\n")
        z = int(input("Resposta="))
        if z == x + y:  # I want the loop to exit here
            input("\n\nCorreto\nPrima enter para continuar...")
            exit

In this scenario, I want the loop to stop when the condition z == x + y is true. How can I properly use Python exit for loop to break out of the loop?

2

You can use the break statement to exit the loop when the condition is met:

from random import randint
import os

x = randint(1, 11)
y = randint(1, 11)

print("", x, "+", y, "=\n")
z = int(input("Resposta="))

if z == x + y:
    input("\n\nCorreto\nPrima enter para continuar...")

else:
    for z in range(0, 10):
        os.system('CLS')
        input("Incorreto.\n\n Tente de novo...")
        x = randint(1, 11)
        y = randint(1, 11)
        os.system('CLS')
        print("", x, "+", y, "=\n")
        z = int(input("Resposta="))
        if z == x + y:  # I want the loop to exit here
            input("\n\nCorreto\nPrima enter para continuar...")
            break  # Exits the loop
3

You can use exit() to stop the program entirely (which will exit the loop and the program), but this is not always recommended as it terminates the entire script:

from random import randint
import os

x = randint(1, 11)
y = randint(1, 11)

print("", x, "+", y, "=\n")
z = int(input("Resposta="))

if z == x + y:
    input("\n\nCorreto\nPrima enter para continuar...")

else:
    for z in range(0, 10):
        os.system('CLS')
        input("Incorreto.\n\n Tente de novo...")
        x = randint(1, 11)
        y = randint(1, 11)
        os.system('CLS')
        print("", x, "+", y, "=\n")
        z = int(input("Resposta="))
        if z == x + y:  # I want the loop to exit here
            input("\n\nCorreto\nPrima enter para continuar...")
            exit()  # Exits the program entirely
4

If your loop is inside a function, you can use return to exit the function and stop the loop:

from random import randint
import os

def run_game():
    x = randint(1, 11)
    y = randint(1, 11)

    print("", x, "+", y, "=\n")
    z = int(input("Resposta="))

    if z == x + y:
        input("\n\nCorreto\nPrima enter para continuar...")

    else:
        for z in range(0, 10):
            os.system('CLS')
            input("Incorreto.\n\n Tente de novo...")
            x = randint(1, 11)
            y = randint(1, 11)
            os.system('CLS')
            print("", x, "+", y, "=\n")
            z = int(input("Resposta="))
            if z == x + y:  # I want the loop to exit here
                input("\n\nCorreto\nPrima enter para continuar...")
                return  # Exits the loop and the function

run_game()

The above solution ensures the loop exits when the condition z == x + y is true, with the keyword python exit for loop properly addressed in each context.