If you’re someone who enjoys combining logic and compactness, list comprehensions are a fantastic way to solve this. You can use a set within the comprehension for a streamlined solution.
Here’s how:
lseparatedOrbList = [1, 2, 2, 3, 4, 4, 5, 5, 5, 6]
seen = set()
unique_list = [item for item in lseparatedOrbList if not (item in seen or seen.add(item))]
print(unique_list) # Output: [1, 2, 3, 4, 5, 6]
This method is concise yet elegant and handles the Python dedupe list challenge effectively.